Distance from ирбит to Jamestown
Driving route: -- ( - )
Driving route: -- ( - )
Extended route information
The flight distance between the nearest airports ирбит (SVX) and Jamestown (YWG) is 7,941.47 km. This corresponds to an approximate flight time of 9h 50min. Similar flight routes: SVX → HIB , SVX → MSP , SVX → DLH , SVX → SUX , UFA → YWG
Bearing: 263.75° (W)The initial bearing on the course from ирбит to Jamestown is 263.75° and the compass direction is W.
Midpoint: 81.25361,-55.0637The geographic midpoint between ирбит and Jamestown is in 4,131.86 km distance between both points in a bearing of 263.75°. It is located in Greenland (Kalaallit Nunaat).
Distance: 8,263.72 kmThe shortest distance (air line) between ирбит and Jamestown is 8,263.72 km.
Driving route: -- ( - )The shortest route between ирбит and Jamestown is according to the route planner. The driving time is approx. . Half of the trip is reached in .
Time difference: -10hThe time difference between ирбит (Asia/Yekaterinburg) and Jamestown (America/Chicago) is -10 hours. This means that it is now 16:42 (02.05.2024) in ирбит and 06:42 (02.05.2024) in Jamestown.
How is the distance calculated?
To calculate the distance between ирбит and Jamestown, the place names are converted into coordinates (latitude and longitude). The respective geographic centre is used for cities, regions and countries. To calculate the distance the Haversine formula is applied.