Distance from Aleksandrovsk to Alexandria
Driving route: -- ( - )
Driving route: -- ( - )
Extended route information
The flight distance between the nearest airports Aleksandrovsk (SVX) and Alexandria (DCA) is 8,367.18 km. This corresponds to an approximate flight time of 10h 20min. Similar flight routes: SVX → IAD , SVX → BWI , SVX → RIC , SVX → PHF , UFA → DCA
Bearing: 256.78° (WSW)The initial bearing on the course from Aleksandrovsk to Alexandria is 256.78° and the compass direction is WSW.
Midpoint: 69.4942,-36.01018The geographic midpoint between Aleksandrovsk and Alexandria is in 4,174.86 km distance between both points in a bearing of 256.78°. It is located in Greenland (Kalaallit Nunaat).
Distance: 8,349.71 kmThe shortest distance (air line) between Aleksandrovsk and Alexandria is 8,349.71 km.
Driving route: -- ( - )The shortest route between Aleksandrovsk and Alexandria is according to the route planner. The driving time is approx. . Half of the trip is reached in .
Time difference: -9hThe time difference between Aleksandrovsk (Asia/Yekaterinburg) and Alexandria (America/New_York) is -9 hours. This means that it is now 05:09 (09.06.2024) in Aleksandrovsk and 20:09 (08.06.2024) in Alexandria.
How is the distance calculated?
To calculate the distance between Aleksandrovsk and Alexandria, the place names are converted into coordinates (latitude and longitude). The respective geographic centre is used for cities, regions and countries. To calculate the distance the Haversine formula is applied.
Similar routes:
Similar distance (± 0.5%)
Alexandria is just as far away from Aleksandrovsk as Aleksandrovsk from Jakarta (8,465 km), New York City (8,053 km), Kinshasa (7,977 km), Luanda (8,528 km), Chicago (8,338 km), Brooklyn (8,058 km), Queens (8,050 km), Camayenne (8,037 km), Conakry (8,036 km), Bandung (8,571 km).