Distance from Aleksandrovsk to Saint-Petersburg
Driving route: -- ( - )
Driving route: -- ( - )
Extended route information
The flight distance between the nearest airports Aleksandrovsk (SVX) and Saint-Petersburg (LED) is 1,540.17 km. This corresponds to an approximate flight time of 2h 18min. Similar flight routes: SVX → HEL , SVX → TLL , SVX → RIX , SVX → SVO , UFA → LED
Bearing: 273.23° (W)The initial bearing on the course from Aleksandrovsk to Saint-Petersburg is 273.23° and the compass direction is W.
Midpoint: 60.26058,44.12089The geographic midpoint between Aleksandrovsk and Saint-Petersburg is in 764.65 km distance between both points in a bearing of 273.23°. It is located in Russia, Vologda Oblast, Nyuksensky District, Городищенское сельское поселение (Россия, Вологодская область, Нюксенский район, Городищенское сельское поселение).
Distance: 1,529.29 kmThe shortest distance (air line) between Aleksandrovsk and Saint-Petersburg is 1,529.29 km.
Driving route: -- ( - )The shortest route between Aleksandrovsk and Saint-Petersburg is according to the route planner. The driving time is approx. . Half of the trip is reached in .
Time difference: -2hThe time difference between Aleksandrovsk (Asia/Yekaterinburg) and Saint-Petersburg (Europe/Moscow) is -2 hours. This means that it is now 06:21 (09.06.2024) in Aleksandrovsk and 04:21 (09.06.2024) in Saint-Petersburg.
How is the distance calculated?
To calculate the distance between Aleksandrovsk and Saint-Petersburg, the place names are converted into coordinates (latitude and longitude). The respective geographic centre is used for cities, regions and countries. To calculate the distance the Haversine formula is applied.
Similar routes:
Similar distance (± 0.5%)
Saint-Petersburg is just as far away from Aleksandrovsk as Aleksandrovsk from Saint Petersburg (1,529 km), Novosibirsk (1,586 km), Kalininskiy (1,524 km), Astrakhan (1,559 km).