Distance from Bogdanovich to Tianshui
Driving route: -- ( - )
Driving route: -- ( - )
Extended route information
The flight distance between the nearest airports Bogdanovich (SVX) and Tianshui (XIY) is 4,283.90 km. This corresponds to an approximate flight time of 5h 32min. Similar flight routes: SVX → CTU , SVX → CKG , SVX → TYN , SVX → CGO , UFA → XIY
Bearing: 126.58° (SE)The initial bearing on the course from Bogdanovich to Tianshui is 126.58° and the compass direction is SE.
Midpoint: 47.71725,88.4901The geographic midpoint between Bogdanovich and Tianshui is in 2,044.30 km distance between both points in a bearing of 126.58°. It is located in China, Xinjiang, Altay City (中国, 新疆维吾尔自治区, 阿勒泰市 (Altay)).
Distance: 4,088.60 kmThe shortest distance (air line) between Bogdanovich and Tianshui is 4,088.60 km.
Driving route: -- ( - )The shortest route between Bogdanovich and Tianshui is according to the route planner. The driving time is approx. . Half of the trip is reached in .
Time difference: 3hThe time difference between Bogdanovich (Asia/Yekaterinburg) and Tianshui (Asia/Shanghai) is 3 hours. This means that it is now 07:25 (08.06.2024) in Bogdanovich and 10:25 (08.06.2024) in Tianshui.
How is the distance calculated?
To calculate the distance between Bogdanovich and Tianshui, the place names are converted into coordinates (latitude and longitude). The respective geographic centre is used for cities, regions and countries. To calculate the distance the Haversine formula is applied.