Distance from Botshabelo to San-Jose
Driving route: -- ( - )
Driving route: -- ( - )
Extended route information
The flight distance between the nearest airports Botshabelo (JNB) and San-Jose (SJC) is 16,986.02 km. This corresponds to an approximate flight time of 20h 29min. Similar flight routes: JNB → OAK , JNB → SFO , JNB → SMF , JNB → RNO , DUR → SJC
Bearing: 295.50° (WNW)The initial bearing on the course from Botshabelo to San-Jose is 295.50° and the compass direction is WNW.
Midpoint: 14.4971,-38.17471The geographic midpoint between Botshabelo and San-Jose is in 8,489.48 km distance between both points in a bearing of 295.50°.
Distance: 16,978.95 kmThe shortest distance (air line) between Botshabelo and San-Jose is 16,978.95 km.
Driving route: -- ( - )The shortest route between Botshabelo and San-Jose is according to the route planner. The driving time is approx. . Half of the trip is reached in .
Time difference: -9hThe time difference between Botshabelo (Africa/Johannesburg) and San-Jose (America/Los_Angeles) is -9 hours. This means that it is now 20:22 (17.05.2024) in Botshabelo and 11:22 (17.05.2024) in San-Jose.
How is the distance calculated?
To calculate the distance between Botshabelo and San-Jose, the place names are converted into coordinates (latitude and longitude). The respective geographic centre is used for cities, regions and countries. To calculate the distance the Haversine formula is applied.
Similar routes:
Similar distance (± 0.5%)
San-Jose is just as far away from Botshabelo as Botshabelo from Los Angeles (16,673 km), San Diego (16,568 km), Tijuana (16,551 km), San Jose (16,979 km), San Francisco (17,017 km), Mexicali (16,408 km), Seattle (16,670 km), Portland (16,792 km), Las Vegas (16,389 km), Vancouver (16,635 km).