Distance from CLE to ABV
Driving route: -- ( - )
Driving route: -- ( - )
Extended route information
The flight distance between airports Cleveland Hopkins International Airport (CLE) and Nnamdi Azikiwe International Airport (ABV) is 9,281.59 km. This corresponds to an approximate flight time of 11h 25min. Similar flight routes: CLE → KAN , CLE → QUO , CLE → LOS , CLE → NIM , DTW → ABV
Bearing: 112.29° (ESE)The initial bearing on the course from CLE to ABV is 112.29° and the compass direction is ESE.
Midpoint: 33.2148,-29.62236The geographic midpoint between CLE and ABV is in 4,636.57 km distance between both points in a bearing of 112.29°.
Distance: 9,273.13 kmThe shortest distance (air line) between CLE and ABV is 9,273.13 km.
Driving route: -- ( - )The shortest route between CLE and ABV is according to the route planner. The driving time is approx. . Half of the trip is reached in .
Time difference: 5hThe time difference between CLE (America/New_York) and ABV (Africa/Lagos) is 5 hours. This means that it is now 08:21 (01.06.2024) in CLE and 13:21 (01.06.2024) in ABV.
How is the distance calculated?
To calculate the distance between CLE and ABV, the place names are converted into coordinates (latitude and longitude). The respective geographic centre is used for cities, regions and countries. To calculate the distance the Haversine formula is applied.
Similar routes:
Similar distance (± 0.5%)
ABV is just as far away from CLE as CLE from Lagos (9,138 km), Cairo (9,518 km), Alexandria (9,339 km), Kano (9,159 km), Ibadan (9,113 km), Ankara (8,828 km), Giza (9,520 km), Al Mawşil al Jadīdah (9,716 km), Accra (8,904 km), Beirut (9,479 km).