Distance from CLE to PVR
Driving route: -- ( - )
Driving route: -- ( - )
Extended route information
The flight distance between airports Cleveland Hopkins International Airport (CLE) and Licenciado Gustavo Díaz Ordaz International Airport (PVR) is 3,184.60 km. This corresponds to an approximate flight time of 4h 14min. Similar flight routes: CLE → GDL , CLE → SJD , CLE → MEX , CLE → ACA , DTW → PVR
Bearing: 223.77° (SW)The initial bearing on the course from CLE to PVR is 223.77° and the compass direction is SW.
Midpoint: 31.57358,-94.85838The geographic midpoint between CLE and PVR is in 1,593.16 km distance between both points in a bearing of 223.77°. It is located in United States of America, Texas, Nacogdoches County.
Distance: 3,186.32 kmThe shortest distance (air line) between CLE and PVR is 3,186.32 km.
Driving route: -- ( - )The shortest route between CLE and PVR is according to the route planner. The driving time is approx. . Half of the trip is reached in .
Time difference: -2hThe time difference between CLE (America/New_York) and PVR (America/Mexico_City) is -2 hours. This means that it is now 18:39 (02.06.2024) in CLE and 16:39 (02.06.2024) in PVR.
How is the distance calculated?
To calculate the distance between CLE and PVR, the place names are converted into coordinates (latitude and longitude). The respective geographic centre is used for cities, regions and countries. To calculate the distance the Haversine formula is applied.
Similar routes:
Similar distance (± 0.5%)
PVR is just as far away from CLE as CLE from Los Angeles (3,278 km), Guadalajara (3,070 km), San Diego (3,254 km), Tijuana (3,251 km), Zapopan (3,064 km), Guatemala City (3,092 km), Managua (3,284 km), Tegucigalpa (3,083 km), Mexicali (3,117 km), Seattle (3,244 km).