Distance from JAX to SJC
Driving route: -- ( - )
Driving route: -- ( - )
Extended route information
The flight distance between airports Jacksonville International Airport (JAX) and Norman Y. Mineta San Jose International Airport (SJC) is 3,768.66 km. This corresponds to an approximate flight time of 4h 56min. Similar flight routes: JAX → OAK , JAX → SFO , JAX → SMF , JAX → RNO , DAB → SJC
Bearing: 281.64° (WNW)The initial bearing on the course from JAX to SJC is 281.64° and the compass direction is WNW.
Midpoint: 35.61532,-100.96115The geographic midpoint between JAX and SJC is in 1,880.62 km distance between both points in a bearing of 281.64°. It is located in United States of America, Texas, Gray County.
Distance: 3,761.24 kmThe shortest distance (air line) between JAX and SJC is 3,761.24 km.
Driving route: -- ( - )The shortest route between JAX and SJC is according to the route planner. The driving time is approx. . Half of the trip is reached in .
Time difference: -3hThe time difference between JAX (America/New_York) and SJC (America/Los_Angeles) is -3 hours. This means that it is now 22:21 (04.06.2024) in JAX and 19:21 (04.06.2024) in SJC.
How is the distance calculated?
To calculate the distance between JAX and SJC, the place names are converted into coordinates (latitude and longitude). The respective geographic centre is used for cities, regions and countries. To calculate the distance the Haversine formula is applied.