Distance from Kamensk-Ural’skiy to Queens
Driving route: -- ( - )
Driving route: -- ( - )
Extended route information
The flight distance between the nearest airports Kamensk-Ural’skiy (SVX) and Queens (LGA) is 8,462.00 km. This corresponds to an approximate flight time of 10h 27min. Similar flight routes: SVX → JFK , SVX → EWR , SVX → PHL , SVX → BDL , UFA → LGA
Bearing: 259.99° (W)The initial bearing on the course from Kamensk-Ural’skiy to Queens is 259.99° and the compass direction is W.
Midpoint: 70.406,-26.91274The geographic midpoint between Kamensk-Ural’skiy and Queens is in 4,219.37 km distance between both points in a bearing of 259.99°. It is located in Greenland (Kalaallit Nunaat).
Distance: 8,438.75 kmThe shortest distance (air line) between Kamensk-Ural’skiy and Queens is 8,438.75 km.
Driving route: -- ( - )The shortest route between Kamensk-Ural’skiy and Queens is according to the route planner. The driving time is approx. . Half of the trip is reached in .
Time difference: -9hThe time difference between Kamensk-Ural’skiy (Asia/Yekaterinburg) and Queens (America/New_York) is -9 hours. This means that it is now 00:11 (11.06.2024) in Kamensk-Ural’skiy and 15:11 (10.06.2024) in Queens.
How is the distance calculated?
To calculate the distance between Kamensk-Ural’skiy and Queens, the place names are converted into coordinates (latitude and longitude). The respective geographic centre is used for cities, regions and countries. To calculate the distance the Haversine formula is applied.