Distance from Kamyshlov to New-York-City
Driving route: -- ( - )
Driving route: -- ( - )
Extended route information
The flight distance between the nearest airports Kamyshlov (SVX) and New-York-City (LGA) is 8,446.70 km. This corresponds to an approximate flight time of 10h 26min. Similar flight routes: SVX → EWR , SVX → JFK , SVX → PHL , SVX → BDL , UFA → LGA
Bearing: 259.72° (W)The initial bearing on the course from Kamyshlov to New-York-City is 259.72° and the compass direction is W.
Midpoint: 70.76348,-27.84078The geographic midpoint between Kamyshlov and New-York-City is in 4,216.98 km distance between both points in a bearing of 259.72°. It is located in Greenland (Kalaallit Nunaat).
Distance: 8,433.97 kmThe shortest distance (air line) between Kamyshlov and New-York-City is 8,433.97 km.
Driving route: -- ( - )The shortest route between Kamyshlov and New-York-City is according to the route planner. The driving time is approx. . Half of the trip is reached in .
Time difference: -9hThe time difference between Kamyshlov (Asia/Yekaterinburg) and New-York-City (America/New_York) is -9 hours. This means that it is now 02:44 (24.05.2024) in Kamyshlov and 17:44 (23.05.2024) in New-York-City.
How is the distance calculated?
To calculate the distance between Kamyshlov and New-York-City, the place names are converted into coordinates (latitude and longitude). The respective geographic centre is used for cities, regions and countries. To calculate the distance the Haversine formula is applied.