Distance from Lawrence to Sioux-Falls
Driving route: -- ( - )
Driving route: -- ( - )
Extended route information
The shortest distance (air line) between Lawrence and Sioux-Falls is 523.58 km.
Driving route: -- ( - )The shortest route between Lawrence and Sioux-Falls is according to the route planner. The driving time is approx. . Half of the trip is reached in .
Flight route: 393.17 km (0h 57min)The flight distance between the nearest airports Lawrence (MCI) and Sioux-Falls (SUX) is 393.17 km. This corresponds to an approximate flight time of 0h 57min. Similar flight routes: MCI → OMA , MCI → MSP , MCI → DSM , MCI → RST , JLN → SUX
Bearing: 346.48° (NNW)The initial bearing on the course from Lawrence to Sioux-Falls is 346.48° and the compass direction is NNW.
Midpoint: 41.26314,-95.9421The geographic midpoint between Lawrence and Sioux-Falls is in 261.79 km distance between both points in a bearing of 346.48°. It is located in United States of America, Nebraska, Douglas County, Omaha.
Time difference: 0hLawrence and Sioux-Falls are both in the same time zone America/Chicago.
How is the distance calculated?
To calculate the distance between Lawrence and Sioux-Falls, the place names are converted into coordinates (latitude and longitude). The respective geographic centre is used for cities, regions and countries. To calculate the distance the Haversine formula is applied.