Distance from Marbella to Yekaterinburg
Driving route: -- ( - )
Driving route: -- ( - )
Extended route information
The flight distance between the nearest airports Marbella (AGP) and Yekaterinburg (SVX) is 5,264.34 km. This corresponds to an approximate flight time of 6h 41min. Similar flight routes: AGP → UFA , AGP → KZN , AGP → KUF , AGP → TSE , FAO → SVX
Bearing: 65.28° (ENE)The initial bearing on the course from Marbella to Yekaterinburg is 65.28° and the compass direction is ENE.
Midpoint: 51.36614,20.88716The geographic midpoint between Marbella and Yekaterinburg is in 2,619.60 km distance between both points in a bearing of 65.28°. It is located in Polska, Masovian Voivodeship, powiat radomski, Mniszek (Polska, województwo mazowieckie, powiat radomski, Mniszek).
Distance: 5,239.21 kmThe shortest distance (air line) between Marbella and Yekaterinburg is 5,239.21 km.
Driving route: -- ( - )The shortest route between Marbella and Yekaterinburg is according to the route planner. The driving time is approx. . Half of the trip is reached in .
Time difference: 3hThe time difference between Marbella (Europe/Madrid) and Yekaterinburg (Asia/Yekaterinburg) is 3 hours. This means that it is now 06:34 (12.06.2024) in Marbella and 09:34 (12.06.2024) in Yekaterinburg.
How is the distance calculated?
To calculate the distance between Marbella and Yekaterinburg, the place names are converted into coordinates (latitude and longitude). The respective geographic centre is used for cities, regions and countries. To calculate the distance the Haversine formula is applied.
Similar routes:
Similar distance (± 0.5%)
Yekaterinburg is just as far away from Marbella as Marbella from Kinshasa (5,002 km), Tehran (4,984 km), Riyadh (5,049 km), Luanda (5,386 km), Addis Ababa (5,348 km), Sanaa (5,372 km), Isfahan (5,122 km), Brazzaville (4,995 km), Shiraz (5,328 km).