Distance from McKinley-Park to Alexandria
Driving route: -- ( - )
Driving route: -- ( - )
Extended route information
The flight distance between the nearest airports McKinley-Park (MDW) and Alexandria (DCA) is 961.55 km. This corresponds to an approximate flight time of 1h 37min. Similar flight routes: MDW → IAD , MDW → BWI , MDW → RIC , MDW → PHF , ORD → DCA
Bearing: 110.49° (ESE)The initial bearing on the course from McKinley-Park to Alexandria is 110.49° and the compass direction is ESE.
Midpoint: 40.43997,-82.24082The geographic midpoint between McKinley-Park and Alexandria is in 480.48 km distance between both points in a bearing of 110.49°. It is located in United States of America, Ohio, Knox County.
Distance: 960.95 kmThe shortest distance (air line) between McKinley-Park and Alexandria is 960.95 km.
Driving route: -- ( - )The shortest route between McKinley-Park and Alexandria is according to the route planner. The driving time is approx. . Half of the trip is reached in .
Time difference: 1hThe time difference between McKinley-Park (America/Chicago) and Alexandria (America/New_York) is 1 hours. This means that it is now 09:14 (21.05.2024) in McKinley-Park and 10:14 (21.05.2024) in Alexandria.
How is the distance calculated?
To calculate the distance between McKinley-Park and Alexandria, the place names are converted into coordinates (latitude and longitude). The respective geographic centre is used for cities, regions and countries. To calculate the distance the Haversine formula is applied.
Similar routes:
Similar distance (± 0.5%)
Alexandria is just as far away from McKinley-Park as McKinley-Park from Charlotte (944 km), Baltimore (975 km), Washington (958 km).