Distance from Moquegua to Alexandria
Driving route: -- ( - )
Driving route: -- ( - )
Extended route information
The flight distance between the nearest airports Moquegua (CUZ) and Alexandria (DCA) is 6,208.06 km. This corresponds to an approximate flight time of 7h 48min. Similar flight routes: CUZ → IAD , CUZ → BWI , CUZ → RIC , CUZ → PHF , VVI → DCA
Bearing: 354.19° (N)The initial bearing on the course from Moquegua to Alexandria is 354.19° and the compass direction is N.
Midpoint: 10.9457,-73.71557The geographic midpoint between Moquegua and Alexandria is in 3,115.38 km distance between both points in a bearing of 354.19°. It is located in Colombia, Magdalena, Santa Marta.
Distance: 6,230.76 kmThe shortest distance (air line) between Moquegua and Alexandria is 6,230.76 km.
Driving route: -- ( - )The shortest route between Moquegua and Alexandria is according to the route planner. The driving time is approx. . Half of the trip is reached in .
Time difference: 1hThe time difference between Moquegua (America/Lima) and Alexandria (America/New_York) is 1 hours. This means that it is now 21:47 (12.05.2024) in Moquegua and 22:47 (12.05.2024) in Alexandria.
How is the distance calculated?
To calculate the distance between Moquegua and Alexandria, the place names are converted into coordinates (latitude and longitude). The respective geographic centre is used for cities, regions and countries. To calculate the distance the Haversine formula is applied.
Similar routes:
Similar distance (± 0.5%)
Alexandria is just as far away from Moquegua as Moquegua from New York City (6,419 km), Brooklyn (6,411 km), Queens (6,414 km), Philadelphia (6,341 km), Manhattan (6,426 km), San Antonio (5,940 km), The Bronx (6,433 km), Dallas (6,173 km), Austin (5,980 km), Columbus (6,448 km).