Distance from Rondebosch to San-Francisco
Driving route: -- ( - )
Driving route: -- ( - )
Extended route information
The flight distance between the nearest airports Rondebosch (CPT) and San-Francisco (SFO) is 16,488.26 km. This corresponds to an approximate flight time of 19h 53min. Similar flight routes: CPT → OAK , CPT → SJC , CPT → SMF , CPT → RNO , GRJ → SFO
Bearing: 298.66° (WNW)The initial bearing on the course from Rondebosch to San-Francisco is 298.66° and the compass direction is WNW.
Midpoint: 5.66521,-48.09585The geographic midpoint between Rondebosch and San-Francisco is in 8,245.90 km distance between both points in a bearing of 298.66°.
Distance: 16,491.79 kmThe shortest distance (air line) between Rondebosch and San-Francisco is 16,491.79 km.
Driving route: -- ( - )The shortest route between Rondebosch and San-Francisco is according to the route planner. The driving time is approx. . Half of the trip is reached in .
Time difference: -9hThe time difference between Rondebosch (Africa/Johannesburg) and San-Francisco (America/Los_Angeles) is -9 hours. This means that it is now 14:13 (14.06.2024) in Rondebosch and 05:13 (14.06.2024) in San-Francisco.
How is the distance calculated?
To calculate the distance between Rondebosch and San-Francisco, the place names are converted into coordinates (latitude and longitude). The respective geographic centre is used for cities, regions and countries. To calculate the distance the Haversine formula is applied.
Similar routes:
Similar distance (± 0.5%)
San-Francisco is just as far away from Rondebosch as Rondebosch from Los Angeles (16,057 km), San Diego (15,925 km), Tijuana (15,904 km), San Jose (16,441 km), Calgary (15,781 km), San Francisco (16,492 km), Edmonton (15,695 km), Mexicali (15,767 km), Seattle (16,432 km), Portland (16,495 km).