Distance from Seymour to Saint-Petersburg
Driving route: -- ( - )
Driving route: -- ( - )
Extended route information
The flight distance between the nearest airports Seymour (SDF) and Saint-Petersburg (LED) is 7,606.33 km. This corresponds to an approximate flight time of 9h 26min. Similar flight routes: SDF → HEL , SDF → TLL , SDF → RIX , SDF → SVO , IND → LED
Bearing: 74.16° (ENE)The initial bearing on the course from Seymour to Saint-Petersburg is 74.16° and the compass direction is ENE.
Midpoint: 64.42178,-46.96002The geographic midpoint between Seymour and Saint-Petersburg is in 3,788.95 km distance between both points in a bearing of 74.16°. It is located in Greenland (Kalaallit Nunaat).
Distance: 7,577.90 kmThe shortest distance (air line) between Seymour and Saint-Petersburg is 7,577.90 km.
Driving route: -- ( - )The shortest route between Seymour and Saint-Petersburg is according to the route planner. The driving time is approx. . Half of the trip is reached in .
Time difference: 7hThe time difference between Seymour (America/Indiana/Indianapolis) and Saint-Petersburg (Europe/Moscow) is 7 hours. This means that it is now 19:33 (02.06.2024) in Seymour and 02:33 (03.06.2024) in Saint-Petersburg.
How is the distance calculated?
To calculate the distance between Seymour and Saint-Petersburg, the place names are converted into coordinates (latitude and longitude). The respective geographic centre is used for cities, regions and countries. To calculate the distance the Haversine formula is applied.
Similar routes:
Similar distance (± 0.5%)
Saint-Petersburg is just as far away from Seymour as Seymour from Saint Petersburg (7,578 km), Berlin (7,228 km), Salvador (7,579 km), Belo Horizonte (7,869 km), Rome (7,829 km), Brasília (7,253 km), Algiers (7,475 km), Camayenne (7,807 km), Conakry (7,808 km), Minsk (7,894 km).