Distance from Sioux-Falls to Guayaquil
Driving route: -- ( - )
Driving route: -- ( - )
Extended route information
The flight distance between the nearest airports Sioux-Falls (SUX) and Guayaquil (LTX) is 5,243.99 km. This corresponds to an approximate flight time of 6h 40min. Similar flight routes: SUX → UIO , SUX → BOG , SUX → LIM , SUX → PTY , OMA → LTX
Bearing: 161.66° (SSE)The initial bearing on the course from Sioux-Falls to Guayaquil is 161.66° and the compass direction is SSE.
Midpoint: 20.87282,-86.95186The geographic midpoint between Sioux-Falls and Guayaquil is in 2,678.57 km distance between both points in a bearing of 161.66°. It is located in Mexico, Quintana Roo, Benito Juárez (México, Quintana Roo, Benito Juárez).
Distance: 5,357.13 kmThe shortest distance (air line) between Sioux-Falls and Guayaquil is 5,357.13 km.
Driving route: -- ( - )The shortest route between Sioux-Falls and Guayaquil is according to the route planner. The driving time is approx. . Half of the trip is reached in .
Time difference: 0hSioux-Falls and Guayaquil are both in the same time zone America/Chicago.
How is the distance calculated?
To calculate the distance between Sioux-Falls and Guayaquil, the place names are converted into coordinates (latitude and longitude). The respective geographic centre is used for cities, regions and countries. To calculate the distance the Haversine formula is applied.
Similar routes:
Similar distance (± 0.5%)
Guayaquil is just as far away from Sioux-Falls as Sioux-Falls from Quito (5,193 km), Ciudad Guayana (5,120 km).