Distance from Sovetsk to Alexandria
Driving route: -- ( - )
Driving route: -- ( - )
Extended route information
The flight distance between the nearest airports Sovetsk (VNO) and Alexandria (DCA) is 7,086.71 km. This corresponds to an approximate flight time of 8h 50min. Similar flight routes: VNO → IAD , VNO → BWI , VNO → RIC , VNO → PHF , GDN → DCA
Bearing: 256.30° (WSW)The initial bearing on the course from Sovetsk to Alexandria is 256.30° and the compass direction is WSW.
Midpoint: 58.3305,-37.72718The geographic midpoint between Sovetsk and Alexandria is in 3,536.26 km distance between both points in a bearing of 256.30°.
Distance: 7,072.51 kmThe shortest distance (air line) between Sovetsk and Alexandria is 7,072.51 km.
Driving route: -- ( - )The shortest route between Sovetsk and Alexandria is according to the route planner. The driving time is approx. . Half of the trip is reached in .
Time difference: -6hThe time difference between Sovetsk (Europe/Kaliningrad) and Alexandria (America/New_York) is -6 hours. This means that it is now 22:48 (01.06.2024) in Sovetsk and 16:48 (01.06.2024) in Alexandria.
How is the distance calculated?
To calculate the distance between Sovetsk and Alexandria, the place names are converted into coordinates (latitude and longitude). The respective geographic centre is used for cities, regions and countries. To calculate the distance the Haversine formula is applied.