Distance from Yemanzhelinsk to Alexandria
Driving route: -- ( - )
Driving route: -- ( - )
Extended route information
The flight distance between the nearest airports Yemanzhelinsk (SVX) and Alexandria (DCA) is 8,901.07 km. This corresponds to an approximate flight time of 10h 58min. Similar flight routes: SVX → IAD , SVX → BWI , SVX → RIC , SVX → PHF , UFA → DCA
Bearing: 260.34° (W)The initial bearing on the course from Yemanzhelinsk to Alexandria is 260.34° and the compass direction is W.
Midpoint: 70.26671,-29.27441The geographic midpoint between Yemanzhelinsk and Alexandria is in 4,441.26 km distance between both points in a bearing of 260.34°. It is located in Greenland (Kalaallit Nunaat).
Distance: 8,882.52 kmThe shortest distance (air line) between Yemanzhelinsk and Alexandria is 8,882.52 km.
Driving route: -- ( - )The shortest route between Yemanzhelinsk and Alexandria is according to the route planner. The driving time is approx. . Half of the trip is reached in .
Time difference: -9hThe time difference between Yemanzhelinsk (Asia/Yekaterinburg) and Alexandria (America/New_York) is -9 hours. This means that it is now 07:32 (29.05.2024) in Yemanzhelinsk and 22:32 (28.05.2024) in Alexandria.
How is the distance calculated?
To calculate the distance between Yemanzhelinsk and Alexandria, the place names are converted into coordinates (latitude and longitude). The respective geographic centre is used for cities, regions and countries. To calculate the distance the Haversine formula is applied.
Similar routes:
Similar distance (± 0.5%)
Alexandria is just as far away from Yemanzhelinsk as Yemanzhelinsk from New York City (8,584 km), Chicago (8,877 km), Toronto (8,455 km), Brooklyn (8,588 km), Queens (8,581 km), Philadelphia (8,701 km), Harare (8,565 km), Manhattan (8,575 km), The Bronx (8,565 km), Makassar (8,527 km).