Distance from gravitationally.adornment.tourniquets to Acapulco-de-Juárez
Driving route: -- ( - )
Driving route: -- ( - )
Extended route information
The flight distance between the nearest airports -20.73158,-145.19387 (PPT) and Acapulco-de-Juárez (ACA) is 6,467.20 km. This corresponds to an approximate flight time of 8h 6min. Similar flight routes: PPT → MEX , PPT → GDL , PPT → PVR , PPT → MTY , RAR → ACA
Bearing: 49.78° (NE)The initial bearing on the course from -20.73158,-145.19387 to Acapulco-de-Juárez is 49.78° and the compass direction is NE.
Midpoint: -2.09561,-122.26715The geographic midpoint between -20.73158,-145.19387 and Acapulco-de-Juárez is in 3,236.25 km distance between both points in a bearing of 49.78°.
Distance: 6,472.49 kmThe shortest distance (air line) between -20.73158,-145.19387 and Acapulco-de-Juárez is 6,472.49 km.
Driving route: -- ( - )The shortest route between -20.73158,-145.19387 and Acapulco-de-Juárez is according to the route planner. The driving time is approx. . Half of the trip is reached in .
Time difference: 4hThe time difference between -20.73158,-145.19387 (Etc/GMT+10) and Acapulco-de-Juárez (America/Mexico_City) is 4 hours. This means that it is now 20:52 (07.07.2024) in -20.73158,-145.19387 and 00:52 (08.07.2024) in Acapulco-de-Juárez.
How is the distance calculated?
To calculate the distance between -20.73158,-145.19387 and Acapulco-de-Juárez, the place names are converted into coordinates (latitude and longitude). The respective geographic centre is used for cities, regions and countries. To calculate the distance the Haversine formula is applied.
Similar routes:
Similar distance (± 0.5%)
Acapulco-de-Juárez is just as far away from -20.73158,-145.19387 as -20.73158,-145.19387 from Mexico City (6,714 km), Sydney (6,354 km), Los Angeles (6,727 km), Brisbane (6,254 km), Iztapalapa (6,714 km), Ecatepec de Morelos (6,732 km), Guadalajara (6,468 km), Puebla (6,763 km), San Diego (6,648 km), Tijuana (6,635 km).