Distance from chunks.elongating.deepened to San-Jose
Driving route: -- ( - )
Driving route: -- ( - )
Extended route information
The flight distance between the nearest airports 18.80209,94.76 (RGN) and San-Jose (SJC) is 12,701.87 km. This corresponds to an approximate flight time of 15h 26min. Similar flight routes: RGN → OAK , RGN → SFO , RGN → SMF , RGN → RNO , MDL → SJC
Bearing: 81.61° (E)The initial bearing on the course from 18.80209,94.76 to San-Jose is 81.61° and the compass direction is E.
Midpoint: 58.63167,151.7117The geographic midpoint between 18.80209,94.76 and San-Jose is in 6,343.60 km distance between both points in a bearing of 81.61°.
Distance: 12,687.20 kmThe shortest distance (air line) between 18.80209,94.76 and San-Jose is 12,687.20 km.
Driving route: -- ( - )The shortest route between 18.80209,94.76 and San-Jose is according to the route planner. The driving time is approx. . Half of the trip is reached in .
Time difference: -13.5hThe time difference between 18.80209,94.76 (Asia/Yangon) and San-Jose (America/Los_Angeles) is -13.5 hours. This means that it is now 09:37 (29.06.2024) in 18.80209,94.76 and 20:07 (28.06.2024) in San-Jose.
How is the distance calculated?
To calculate the distance between 18.80209,94.76 and San-Jose, the place names are converted into coordinates (latitude and longitude). The respective geographic centre is used for cities, regions and countries. To calculate the distance the Haversine formula is applied.
Similar routes:
Similar distance (± 0.5%)
San-Jose is just as far away from 18.80209,94.76 as 18.80209,94.76 from New York City (13,296 km), Los Angeles (13,178 km), Chicago (13,266 km), Toronto (13,040 km), Brooklyn (13,302 km), Queens (13,297 km), Montréal (12,768 km), Manhattan (13,288 km), The Bronx (13,279 km), San Jose (12,687 km).