Distance from Argayash to Queens
Driving route: -- ( - )
Driving route: -- ( - )
Extended route information
The flight distance between the nearest airports Argayash (SVX) and Queens (LGA) is 8,512.36 km. This corresponds to an approximate flight time of 10h 30min. Similar flight routes: SVX → JFK , SVX → EWR , SVX → PHL , SVX → BDL , UFA → LGA
Bearing: 260.60° (W)The initial bearing on the course from Argayash to Queens is 260.60° and the compass direction is W.
Midpoint: 69.9218,-25.51834The geographic midpoint between Argayash and Queens is in 4,244.47 km distance between both points in a bearing of 260.60°. It is located in Greenland (Kalaallit Nunaat).
Distance: 8,488.94 kmThe shortest distance (air line) between Argayash and Queens is 8,488.94 km.
Driving route: -- ( - )The shortest route between Argayash and Queens is according to the route planner. The driving time is approx. . Half of the trip is reached in .
Time difference: -9hThe time difference between Argayash (Asia/Yekaterinburg) and Queens (America/New_York) is -9 hours. This means that it is now 04:14 (30.06.2024) in Argayash and 19:14 (29.06.2024) in Queens.
How is the distance calculated?
To calculate the distance between Argayash and Queens, the place names are converted into coordinates (latitude and longitude). The respective geographic centre is used for cities, regions and countries. To calculate the distance the Haversine formula is applied.