Distance from CLE to Acapulco-de-Juárez
Driving route: -- ( - )
Driving route: -- ( - )
Extended route information
The flight distance between airports Cleveland Hopkins International Airport (CLE) and Acapulco de Juárez (ACA) is 3,226.44 km. This corresponds to an approximate flight time of 4h 17min. Similar flight routes: CLE → MEX , CLE → GDL , CLE → PVR , CLE → MTY , DTW → ACA
Bearing: 212.37° (SSW)The initial bearing on the course from CLE to Acapulco-de-Juárez is 212.37° and the compass direction is SSW.
Midpoint: 29.4372,-91.97291The geographic midpoint between CLE and Acapulco-de-Juárez is in 1,614.25 km distance between both points in a bearing of 212.37°. It is located in United States of America.
Distance: 3,228.50 kmThe shortest distance (air line) between CLE and Acapulco-de-Juárez is 3,228.50 km.
Driving route: -- ( - )The shortest route between CLE and Acapulco-de-Juárez is according to the route planner. The driving time is approx. . Half of the trip is reached in .
Time difference: -2hThe time difference between CLE (America/New_York) and Acapulco-de-Juárez (America/Mexico_City) is -2 hours. This means that it is now 11:32 (14.06.2024) in CLE and 09:32 (14.06.2024) in Acapulco-de-Juárez.
How is the distance calculated?
To calculate the distance between CLE and Acapulco-de-Juárez, the place names are converted into coordinates (latitude and longitude). The respective geographic centre is used for cities, regions and countries. To calculate the distance the Haversine formula is applied.
Similar routes:
Similar distance (± 0.5%)
Acapulco-de-Juárez is just as far away from CLE as CLE from Los Angeles (3,278 km), Guadalajara (3,070 km), San Diego (3,254 km), Tijuana (3,251 km), Guatemala City (3,092 km), Managua (3,284 km), Tegucigalpa (3,083 km), Mexicali (3,117 km), Seattle (3,244 km), Acapulco de Juárez (3,231 km).