Distance from Cleveland to Acapulco-de-Juárez
Driving route: -- ( - )
Driving route: -- ( - )
Extended route information
The flight distance between the nearest airports Cleveland (CLE) and Acapulco-de-Juárez (ACA) is 3,242.03 km. This corresponds to an approximate flight time of 4h 18min. Similar flight routes: CLE → MEX , CLE → GDL , CLE → PVR , CLE → MTY , ERI → ACA
Bearing: 212.48° (SSW)The initial bearing on the course from Cleveland to Acapulco-de-Juárez is 212.48° and the compass direction is SSW.
Midpoint: 29.48652,-91.91143The geographic midpoint between Cleveland and Acapulco-de-Juárez is in 1,622.05 km distance between both points in a bearing of 212.48°. It is located in United States of America, Louisiana, Iberia Parish.
Distance: 3,244.10 kmThe shortest distance (air line) between Cleveland and Acapulco-de-Juárez is 3,244.10 km.
Driving route: -- ( - )The shortest route between Cleveland and Acapulco-de-Juárez is according to the route planner. The driving time is approx. . Half of the trip is reached in .
Time difference: -2hThe time difference between Cleveland (America/New_York) and Acapulco-de-Juárez (America/Mexico_City) is -2 hours. This means that it is now 06:37 (15.06.2024) in Cleveland and 04:37 (15.06.2024) in Acapulco-de-Juárez.
How is the distance calculated?
To calculate the distance between Cleveland and Acapulco-de-Juárez, the place names are converted into coordinates (latitude and longitude). The respective geographic centre is used for cities, regions and countries. To calculate the distance the Haversine formula is applied.
Similar routes:
Similar distance (± 0.5%)
Acapulco-de-Juárez is just as far away from Cleveland as Cleveland from Los Angeles (3,291 km), Guadalajara (3,086 km), San Diego (3,268 km), Tijuana (3,265 km), Guatemala City (3,105 km), Managua (3,295 km), Tegucigalpa (3,095 km), Mexicali (3,131 km), Seattle (3,252 km), Acapulco de Juárez (3,246 km).